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x^2+43x-240=0
a = 1; b = 43; c = -240;
Δ = b2-4ac
Δ = 432-4·1·(-240)
Δ = 2809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2809}=53$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(43)-53}{2*1}=\frac{-96}{2} =-48 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(43)+53}{2*1}=\frac{10}{2} =5 $
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